4(x^2)=6(2x)

Solution for 4(x^2)=6(2x) equation:

4(x^2)=6(2x)

We move all terms to the left:

4(x^2)-(6(2x))=0

determiningTheFunctionDomain
4x^2-62x=0

a = 4; b = -62; c = 0;
Δ = b2-4ac
Δ = -622-4·4·0
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-62}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+62}{2*4}=\frac{124}{8}
=15+1/2
$